Factorio Solar Panel Accumulator Ratio

The ratio 100 solar panels to 84 accumulators is optimized for solar panels first than for accumulators. So the op post is 100 accurate. A single solar panel outputs an average of 42 kw over a day and requires 0 84 accumulators to sustain a constant power output through the night.

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Factorio Prints Accumulator Solar Panel 0 84 Ratio Designed By Cilya On The Factorio Forums

Anyone Know How To Easily Check Exact Numbers Of Panels Accumulators On Big Blueprints I M On A Quest To Find The Best Solar Array And Need To Start Working On Ratios Factorio

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0 84 Exact Ratio Solar Panel Layout 4 Substation Symmetrical With Roboport Imgur

The optimal ratio is 0 84 21 25 accumulators per solar panel and 23 8 solar panels per megawatt required by your factory this ratio accounts for solar panels needed to charge the accumulators.

Factorio solar panel accumulator ratio.

It takes 23 8 solar panels to operate 1 mw of factory and charge 20 accumulators to sustain that 1 mw through the night. We could do that the other way around. 8571 3 7 kw solar panels 600 mj capacity of accumulators so the result is we need 25 21 1 190476 period 6 more solar panels than accumulators. Or we can say we need 25 solar panels per 21 accumulators.

I had found that a ratio of 1 2 to 1 5 accumulators per solar panel worked out perfectly fine. Just divide if you need a decimal. For me it is 1 1 mainly because of the spatial design easily tile able and low supply for the slow conbots out of the mk1 personal roboport not because of any other reason. The ratios posted result in more solar panels then are needed to power factory and charge accumulators i had posted this in a topic on the steam forum a week ago when somebody was asking about solar panels and another person brought up the 0 8 1 ratio.

When accumulator and solar tech is first obtained i establish the ratio on a blueprint. Or we can say we need 21 25 0 84 accumulators per solar panel. Note that this isolation is bidirectional. We could do that the other way around.

This means that you need 1 428 mw of production of solar panels and 100mj of storage to provide 1 mw of power over one day night cycle. Notes a single solar panel outputs an average of 42 kw over a day and requires 0 84 accumulators to sustain a constant power output through the night. Reverse operation ratio from decimal needs multiplication and reduction by the largest common divisor. Either network can charge the accumulators and the accumulators can discharge into either network.

Anyway here s the source. We would need the fewest accumulators if we would just draw power from them if solar panels would produce no power at all. Since the maximum input output rate of an accumulator is 300 kw power flow between the two networks will be limited to 300 kw times the number of accumulators 1 5 mw in the example.